过点A(4,-1)和双曲线x^2/9-y^2/16=1右焦点的直线方程
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![过点A(4,-1)和双曲线x^2/9-y^2/16=1右焦点的直线方程](/uploads/image/z/10193582-38-2.jpg?t=%E8%BF%87%E7%82%B9A%284%2C-1%29%E5%92%8C%E5%8F%8C%E6%9B%B2%E7%BA%BFx%5E2%2F9-y%5E2%2F16%3D1%E5%8F%B3%E7%84%A6%E7%82%B9%E7%9A%84%E7%9B%B4%E7%BA%BF%E6%96%B9%E7%A8%8B)
过点A(4,-1)和双曲线x^2/9-y^2/16=1右焦点的直线方程
过点A(4,-1)和双曲线x^2/9-y^2/16=1右焦点的直线方程
过点A(4,-1)和双曲线x^2/9-y^2/16=1右焦点的直线方程
令坐标a(x,y),b(x,y)则有:x^/9-y^/=;x^/9-y^/=;两式相减得:(x+x)(x-x)/9=(y+y)y0=(y+y)/;则 y0=x0.由弦ab过右焦点f(,0)可知直线ab方程为y=x-;则有:y0=x0-;与y0=x0联立解得:x0=-/;