第十六章 分式1.[(x-1)/(x²-x-2)]²÷【(x²-2x+1)/(2-x)】÷[1/(x²+x)]=2.[(a²-5a+6)/(a²-16)]×[(a²+5a+4)/(a²-4)]÷[(a-3)/(a+4)]=
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![第十六章 分式1.[(x-1)/(x²-x-2)]²÷【(x²-2x+1)/(2-x)】÷[1/(x²+x)]=2.[(a²-5a+6)/(a²-16)]×[(a²+5a+4)/(a²-4)]÷[(a-3)/(a+4)]=](/uploads/image/z/1024926-6-6.jpg?t=%E7%AC%AC%E5%8D%81%E5%85%AD%E7%AB%A0+%E5%88%86%E5%BC%8F1.%5B%28x-1%29%2F%28x%26%23178%3B-x-2%29%5D%26%23178%3B%C3%B7%E3%80%90%28x%26%23178%3B-2x%2B1%29%2F%282-x%29%E3%80%91%C3%B7%5B1%2F%28x%26%23178%3B%2Bx%29%5D%3D2.%5B%28a%26%23178%3B-5a%2B6%29%2F%28a%26%23178%3B-16%29%5D%C3%97%5B%28a%26%23178%3B%2B5a%2B4%29%2F%28a%26%23178%3B-4%29%5D%C3%B7%5B%28a-3%29%2F%28a%2B4%29%5D%3D)
第十六章 分式1.[(x-1)/(x²-x-2)]²÷【(x²-2x+1)/(2-x)】÷[1/(x²+x)]=2.[(a²-5a+6)/(a²-16)]×[(a²+5a+4)/(a²-4)]÷[(a-3)/(a+4)]=
第十六章 分式
1.[(x-1)/(x²-x-2)]²÷【(x²-2x+1)/(2-x)】÷[1/(x²+x)]=
2.[(a²-5a+6)/(a²-16)]×[(a²+5a+4)/(a²-4)]÷[(a-3)/(a+4)]=
第十六章 分式1.[(x-1)/(x²-x-2)]²÷【(x²-2x+1)/(2-x)】÷[1/(x²+x)]=2.[(a²-5a+6)/(a²-16)]×[(a²+5a+4)/(a²-4)]÷[(a-3)/(a+4)]=
1.
2.这里的a用x代替.
这个是经过几何画板验算的