设x=a^2*b^2+5, y=2ab-a^2-4a,若x>y,则实数a,b应满足的条件为?
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![设x=a^2*b^2+5, y=2ab-a^2-4a,若x>y,则实数a,b应满足的条件为?](/uploads/image/z/1040211-27-1.jpg?t=%E8%AE%BEx%3Da%5E2%2Ab%5E2%2B5%2C%26%23160%3B+y%3D2ab-a%5E2-4a%2C%E8%8B%A5x%3Ey%2C%E5%88%99%E5%AE%9E%E6%95%B0a%2Cb%E5%BA%94%E6%BB%A1%E8%B6%B3%E7%9A%84%E6%9D%A1%E4%BB%B6%E4%B8%BA%3F%26%23160%3B)
设x=a^2*b^2+5, y=2ab-a^2-4a,若x>y,则实数a,b应满足的条件为?
设x=a^2*b^2+5, y=2ab-a^2-4a,若x>y,则实数a,b应满足的条件为?
设x=a^2*b^2+5, y=2ab-a^2-4a,若x>y,则实数a,b应满足的条件为?
x-y=a^2b^2-2ab+1+a^2+4a+4
=(ab-1)^2+(a+2)^2
x>y,x-y>0
即不能等于0
而等于0时ab-1=0,a+2=0
a=-2,b=1/2
所以a,b应满足的条件为a≠-2且b≠1/2