若方程2x²-(4m+1)x+2m²-1=0 有两个相等的实数根 则求m
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![若方程2x²-(4m+1)x+2m²-1=0 有两个相等的实数根 则求m](/uploads/image/z/1066455-63-5.jpg?t=%E8%8B%A5%E6%96%B9%E7%A8%8B2x%26%23178%3B-%284m%2B1%29x%2B2m%26%23178%3B-1%3D0+%E6%9C%89%E4%B8%A4%E4%B8%AA%E7%9B%B8%E7%AD%89%E7%9A%84%E5%AE%9E%E6%95%B0%E6%A0%B9+%E5%88%99%E6%B1%82m)
若方程2x²-(4m+1)x+2m²-1=0 有两个相等的实数根 则求m
若方程2x²-(4m+1)x+2m²-1=0 有两个相等的实数根 则求m
若方程2x²-(4m+1)x+2m²-1=0 有两个相等的实数根 则求m
(4m+1)*2_8X(2m*2_1)=0
16m*2+8m+1_16m*2+8=0
8m+9=0
m=_9/8
(4m+1)的平方减去4*2*(2m的平方—1)=0 m为-9/8