lim(n-∞)﹙x²/x²-1﹚lim(n-∞)[x²/x²-1﹚]^x
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/05 17:53:33
![lim(n-∞)﹙x²/x²-1﹚lim(n-∞)[x²/x²-1﹚]^x](/uploads/image/z/10777338-18-8.jpg?t=lim%28n-%E2%88%9E%29%EF%B9%99x%26%23178%3B%EF%BC%8Fx%26%23178%3B-1%EF%B9%9Alim%28n-%E2%88%9E%29%5Bx%26%23178%3B%EF%BC%8Fx%26%23178%3B-1%EF%B9%9A%5D%5Ex)
lim(n-∞)﹙x²/x²-1﹚lim(n-∞)[x²/x²-1﹚]^x
lim(n-∞)﹙x²/x²-1﹚
lim(n-∞)[x²/x²-1﹚]^x
lim(n-∞)﹙x²/x²-1﹚lim(n-∞)[x²/x²-1﹚]^x
lim[x²/x²-1﹚]^x
=lim[1+1/(x^2-1)]^x
=lim[1+1/(x^2-1)]^{(x^2-1)]*[x^2/(x^2-1)]}
=lim[1+1/(x^2-1)]^(x^2-1)]
=e(1)、证明:
∴A1B1=(-1,1,0) A1A=(0,0,√2) C1D=(1/2,1/2,0)
∴A1B1·C1D=0 A1A·C1D=0
∴A1B1⊥C1D A1A⊥C1D
又∵A1B1∈平面AA1B1B 且A1A∈平面AA1B1B 且A1A与A1B1不平行
∴C1D⊥平面AA1B1B
(2)、∵AB1=(-1,1,-√2)
∴AB1·C1D=0
∴AB1⊥C1D
∴只要AB1⊥DF时,就会有AB1⊥平面C1DF
又∵DF=(-1/2,1/2,z)
∴AB1·DF=1-z√2
∴当z=1/√2时,AB1⊥DF
即:F点坐标为(0,1,1/√2) 即BB1中点时,会使得AB1⊥平面C1DF
???
lim[x²/x²-1﹚]^x
=lim[1+1/(x^2-1)]^x
=lim[1+1/(x^2-1)]^{(x^2-1)]*[x^2/(x^2-1)]}
=lim[1+1/(x^2-1)]^(x^2-1)]
=e