若(a+1)ˆ2+|b-2|=0,化简a(xˆ2y+xyˆ2)-b(xˆ2y-xyˆ2)=
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若(a+1)ˆ2+|b-2|=0,化简a(xˆ2y+xyˆ2)-b(xˆ2y-xyˆ2)=
若(a+1)ˆ2+|b-2|=0,化简a(xˆ2y+xyˆ2)-b(xˆ2y-xyˆ2)=
若(a+1)ˆ2+|b-2|=0,化简a(xˆ2y+xyˆ2)-b(xˆ2y-xyˆ2)=
(a+1)ˆ2+|b-2|=0
说明
a + 1 = 0
b - 2 = 0
a = -1
b = 2
a(xˆ2y+xyˆ2)-b(xˆ2y-xyˆ2)
= - (xˆ2y+xyˆ2)-2(xˆ2y-xyˆ2)
= -xˆ2y - xyˆ2 - 2xˆ2y + 2xyˆ2
=-3xˆ2y + xyˆ2
(a+1)ˆ2大于等于0,+|b-2|大于等于0,因为(a+1)ˆ2+|b-2|=0,所以(a+1)ˆ2=0,|b-2|=0
所以a=-1,b=2。所以:
a(xˆ2y+xyˆ2)-b(xˆ2y-xyˆ2)
=-(xˆ2y+xyˆ2)-2(xˆ2y-xyˆ2)
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(a+1)ˆ2大于等于0,+|b-2|大于等于0,因为(a+1)ˆ2+|b-2|=0,所以(a+1)ˆ2=0,|b-2|=0
所以a=-1,b=2。所以:
a(xˆ2y+xyˆ2)-b(xˆ2y-xyˆ2)
=-(xˆ2y+xyˆ2)-2(xˆ2y-xyˆ2)
=-3xˆ2y+xyˆ2
=(-3x+y)xy
希望采纳,谢谢!
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