解方程:(3-x)/(1-x)+(x^2-2)/(x^2-8x+7)=1+(x-5)/(x-7)
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![解方程:(3-x)/(1-x)+(x^2-2)/(x^2-8x+7)=1+(x-5)/(x-7)](/uploads/image/z/1095723-27-3.jpg?t=%E8%A7%A3%E6%96%B9%E7%A8%8B%EF%BC%9A%283-x%29%2F%281-x%29%2B%28x%5E2-2%29%2F%28x%5E2-8x%2B7%29%3D1%2B%28x-5%29%2F%28x-7%29)
解方程:(3-x)/(1-x)+(x^2-2)/(x^2-8x+7)=1+(x-5)/(x-7)
解方程:(3-x)/(1-x)+(x^2-2)/(x^2-8x+7)=1+(x-5)/(x-7)
解方程:(3-x)/(1-x)+(x^2-2)/(x^2-8x+7)=1+(x-5)/(x-7)
同乘(x-1)*(x-7)
得(x-3)(x-7)+(x^2-2)=(x-1)*(x-7)+(x-5)(x-1)
即-10x+21-2=-8x+7-6x+5
4x=-7
x=-7/4
同化分母,在分母不为零的前提下解方程,这样就变成了很简单的题.我算了算,x=-7/4