(x+y)³-xy(x+y)=(x+y)*A,则A=?
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![(x+y)³-xy(x+y)=(x+y)*A,则A=?](/uploads/image/z/13893725-29-5.jpg?t=%EF%BC%88x%2By%EF%BC%89%26%23179%3B-xy%EF%BC%88x%2By%EF%BC%89%3D%EF%BC%88x%2By%EF%BC%89%2AA%2C%E5%88%99A%3D%3F)
(x+y)³-xy(x+y)=(x+y)*A,则A=?
(x+y)³-xy(x+y)=(x+y)*A,则A=?
(x+y)³-xy(x+y)=(x+y)*A,则A=?
(x+y)³-xy(x+y)
=(x+y)[(x+y)²-xy]
=(x+y)(x²+2xy+y²-xy)
=(x+y)(x²+xy+y²)
所以A=x²+xy+y²
x的平方加上y的平方加上xy的积