已知函数f(x)=ax^2+bx+1(a不等于0,a,b为实数),设F(x)={①f(x)(x>0)②-f(x)(x<0)}.①:若f(-1...已知函数f(x)=ax^2+bx+1(a不等于0,a,b为实数),设F(x)={①f(x)(x>0)②-f(x)(x<0)}.①:若f(-1)=0且对任意实数
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![已知函数f(x)=ax^2+bx+1(a不等于0,a,b为实数),设F(x)={①f(x)(x>0)②-f(x)(x<0)}.①:若f(-1...已知函数f(x)=ax^2+bx+1(a不等于0,a,b为实数),设F(x)={①f(x)(x>0)②-f(x)(x<0)}.①:若f(-1)=0且对任意实数](/uploads/image/z/1562323-67-3.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3Dax%5E2%2Bbx%2B1%28a%E4%B8%8D%E7%AD%89%E4%BA%8E0%2Ca%2Cb%E4%B8%BA%E5%AE%9E%E6%95%B0%29%2C%E8%AE%BEF%28x%29%3D%EF%BD%9B%E2%91%A0f%28x%29%28x%EF%BC%9E0%29%E2%91%A1-f%28x%29%28x%EF%BC%9C0%29%EF%BD%9D.%E2%91%A0%EF%BC%9A%E8%8B%A5f%EF%BC%88-1...%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3Dax%5E2%2Bbx%2B1%28a%E4%B8%8D%E7%AD%89%E4%BA%8E0%2Ca%2Cb%E4%B8%BA%E5%AE%9E%E6%95%B0%29%2C%E8%AE%BEF%28x%29%3D%EF%BD%9B%E2%91%A0f%28x%29%28x%EF%BC%9E0%29%E2%91%A1-f%28x%29%28x%EF%BC%9C0%29%EF%BD%9D.%E2%91%A0%EF%BC%9A%E8%8B%A5f%EF%BC%88-1%EF%BC%89%3D0%E4%B8%94%E5%AF%B9%E4%BB%BB%E6%84%8F%E5%AE%9E%E6%95%B0)
已知函数f(x)=ax^2+bx+1(a不等于0,a,b为实数),设F(x)={①f(x)(x>0)②-f(x)(x<0)}.①:若f(-1...已知函数f(x)=ax^2+bx+1(a不等于0,a,b为实数),设F(x)={①f(x)(x>0)②-f(x)(x<0)}.①:若f(-1)=0且对任意实数
已知函数f(x)=ax^2+bx+1(a不等于0,a,b为实数),设F(x)={①f(x)(x>0)②-f(x)(x<0)}.①:若f(-1...
已知函数f(x)=ax^2+bx+1(a不等于0,a,b为实数),设F(x)={①f(x)(x>0)②-f(x)(x<0)}.
①:若f(-1)=0且对任意实数x均有f(x)>=0成立,求F(x)表达式.
②:在①的条件下,当x∈[-2,2]时,g(x)=f(x)-kx是单调函数,求实数k的取值范围.
③:设mn<0,m+n>0,a>0,且f(x)满足f(-x)=f(x),试比较F(m)+F(n)与0的大小.
已知函数f(x)=ax^2+bx+1(a不等于0,a,b为实数),设F(x)={①f(x)(x>0)②-f(x)(x<0)}.①:若f(-1...已知函数f(x)=ax^2+bx+1(a不等于0,a,b为实数),设F(x)={①f(x)(x>0)②-f(x)(x<0)}.①:若f(-1)=0且对任意实数
a-b+1=0
b=a+1
f(x)=ax^2+(a+1)x+1=(x+1)(ax+1)
只有当a=1时,f(x)>=0
f(x)=x^2+2x+1
F(x)={①x^2+2x+1(x>0)②-x^2-2x-1(x<0)}
g(x)=x^2+(2-k)x+1
g'(x)=2x+2-k
g'(-2)g(2)=(-2-k)(6-k)>0
k>6或k