解分式方程:1/X-2+1/X-6=1/X-7+1/X-11/X-2+1/X-6=1/X-7+1/X-11/(x-2)-1/(x-1)=1/(x-7)-1/(x-6)(x-1-x+2)/(x-2)(x-1)=(x-6-x+7)/(x-7)(x-6)1/(x-2)(x-1)=1/(x-7)(x-6)(x-2)(x-1)=(x-7)(x-6)x^2-3x+2=x^2-13x+4213x-3x=42-210x=40x=4 为什么要移向才能解
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![解分式方程:1/X-2+1/X-6=1/X-7+1/X-11/X-2+1/X-6=1/X-7+1/X-11/(x-2)-1/(x-1)=1/(x-7)-1/(x-6)(x-1-x+2)/(x-2)(x-1)=(x-6-x+7)/(x-7)(x-6)1/(x-2)(x-1)=1/(x-7)(x-6)(x-2)(x-1)=(x-7)(x-6)x^2-3x+2=x^2-13x+4213x-3x=42-210x=40x=4 为什么要移向才能解](/uploads/image/z/174873-57-3.jpg?t=%E8%A7%A3%E5%88%86%E5%BC%8F%E6%96%B9%E7%A8%8B%EF%BC%9A1%2FX-2%2B1%2FX-6%3D1%2FX-7%2B1%2FX-11%2FX-2%2B1%2FX-6%3D1%2FX-7%2B1%2FX-11%2F%28x-2%29-1%2F%28x-1%29%3D1%2F%28x-7%29-1%2F%28x-6%29%28x-1-x%2B2%29%2F%28x-2%29%28x-1%29%3D%28x-6-x%2B7%29%2F%28x-7%29%28x-6%291%2F%28x-2%29%28x-1%29%3D1%2F%28x-7%29%28x-6%29%28x-2%29%28x-1%29%3D%28x-7%29%28x-6%29x%5E2-3x%2B2%3Dx%5E2-13x%2B4213x-3x%3D42-210x%3D40x%3D4+%E4%B8%BA%E4%BB%80%E4%B9%88%E8%A6%81%E7%A7%BB%E5%90%91%E6%89%8D%E8%83%BD%E8%A7%A3)
解分式方程:1/X-2+1/X-6=1/X-7+1/X-11/X-2+1/X-6=1/X-7+1/X-11/(x-2)-1/(x-1)=1/(x-7)-1/(x-6)(x-1-x+2)/(x-2)(x-1)=(x-6-x+7)/(x-7)(x-6)1/(x-2)(x-1)=1/(x-7)(x-6)(x-2)(x-1)=(x-7)(x-6)x^2-3x+2=x^2-13x+4213x-3x=42-210x=40x=4 为什么要移向才能解
解分式方程:1/X-2+1/X-6=1/X-7+1/X-1
1/X-2+1/X-6=1/X-7+1/X-1
1/(x-2)-1/(x-1)=1/(x-7)-1/(x-6)
(x-1-x+2)/(x-2)(x-1)=(x-6-x+7)/(x-7)(x-6)
1/(x-2)(x-1)=1/(x-7)(x-6)
(x-2)(x-1)=(x-7)(x-6)
x^2-3x+2=x^2-13x+42
13x-3x=42-2
10x=40
x=4 为什么要移向才能解出来
解分式方程:1/X-2+1/X-6=1/X-7+1/X-11/X-2+1/X-6=1/X-7+1/X-11/(x-2)-1/(x-1)=1/(x-7)-1/(x-6)(x-1-x+2)/(x-2)(x-1)=(x-6-x+7)/(x-7)(x-6)1/(x-2)(x-1)=1/(x-7)(x-6)(x-2)(x-1)=(x-7)(x-6)x^2-3x+2=x^2-13x+4213x-3x=42-210x=40x=4 为什么要移向才能解
先看一个式子.1/n - 1/(n+1)=1 / n(n+1).这个等式容易理解,通分就行了.在原式中,x-2比x-1小1,x-7比x-6小1.所以可以把原等式进行移项,目的是通分后使分子为1,从而达到使分子降次的目的,最终把原方程转化为一元一次方程.这样方程就解出来了.
1/X-2+1/X-6=1/X-7+1/X-1
1/(x-2)-1/(x-1)=1/(x-7)-1/(x-6)
(x-1-x+2)/(x-2)(x-1)=(x-6-x+7)/(x-7)(x-6)
1/(x-2)(x-1)=1/(x-7)(x-6)
(x-2)(x-1)=(x-7)(x-6)
x^2-3x+2=x^2-13x+42
13x-3x=42-2
10x=40
x=4
4
1/X-2+1/X-6=1/X-7+1/X
x=4
x=5