若A=(2-1) (2+1) (2^2+1) (2^4+1) ...(2^64+1),则A-1996的末尾数字是?
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![若A=(2-1) (2+1) (2^2+1) (2^4+1) ...(2^64+1),则A-1996的末尾数字是?](/uploads/image/z/1811053-37-3.jpg?t=%E8%8B%A5A%3D%282-1%29+%282%2B1%29+%282%5E2%2B1%29+%282%5E4%2B1%29+...%282%5E64%2B1%29%2C%E5%88%99A-1996%E7%9A%84%E6%9C%AB%E5%B0%BE%E6%95%B0%E5%AD%97%E6%98%AF%3F)
若A=(2-1) (2+1) (2^2+1) (2^4+1) ...(2^64+1),则A-1996的末尾数字是?
若A=(2-1) (2+1) (2^2+1) (2^4+1) ...(2^64+1),则A-1996的末尾数字是?
若A=(2-1) (2+1) (2^2+1) (2^4+1) ...(2^64+1),则A-1996的末尾数字是?
可以不断地用平方差公式算,最后得到A=2^128-1 然后你可以找规律2,4,8,16,32,64,128...个位数字4个一循环,所以2^128各位为6 A的个位为5 A-1996的末尾数字为9