X-2-(x²/ x+2)
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![X-2-(x²/ x+2)](/uploads/image/z/1972949-5-9.jpg?t=X-2-%EF%BC%88x%26sup2%3B%2F+x%2B2%EF%BC%89)
X-2-(x²/ x+2)
X-2-(x²/ x+2)
X-2-(x²/ x+2)
原式=[(x-2)(x+2)/(x+2)-x²/(x+2)
=(x²-4)/(x+2)-x²/(x+2)
=(x²-4-x²)/(x+2)
=-4/(x+2)
原式得x-2-(x+2) 去括号得x-2-x-2 得解=-4
有两个答案.
一个当X是正数时.X-2-(x²/ x+2)
=X-2-(X+2)
=-4
一个当X是负数时:X-2-(x²/ x+2)
=X-2-(-X+2)
=2X-4
原式=[(x-2)(x+2)/(x+2)-x²/(x+2)
=(x²-4)/(x+2)-x²/(x+2)
=(x²-4-x²)/(x+2)
=-4/(x+2)