如果(3x²-2)-(3x²-y)=2,那么代数式(x+y)+3(x-y)-4(x-y-2)的值为
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![如果(3x²-2)-(3x²-y)=2,那么代数式(x+y)+3(x-y)-4(x-y-2)的值为](/uploads/image/z/2536095-39-5.jpg?t=%E5%A6%82%E6%9E%9C%EF%BC%883x%26%23178%3B-2%EF%BC%89-%283x%26%23178%3B-y%29%3D2%2C%E9%82%A3%E4%B9%88%E4%BB%A3%E6%95%B0%E5%BC%8F%28x%2By%29%2B3%28x-y%29-4%28x-y-2%29%E7%9A%84%E5%80%BC%E4%B8%BA)
如果(3x²-2)-(3x²-y)=2,那么代数式(x+y)+3(x-y)-4(x-y-2)的值为
如果(3x²-2)-(3x²-y)=2,那么代数式(x+y)+3(x-y)-4(x-y-2)的值为
如果(3x²-2)-(3x²-y)=2,那么代数式(x+y)+3(x-y)-4(x-y-2)的值为
y-2=2;
y=4;
(x+y)+3(x-y)-4(x-y-2)
=x+y+3x-3y-4x+4y+8
=2y+8
=8+8
=16
原式=y-2=2,所以y=4。 原代数式=x+y+3x-3y-4x+4y+8=2y+8,将y=4代入,得:2*4+8=16