若有理数a,b满足(a-b)²+(-3)×(-1)=1-(b+2)²-(-2),则代数式ab+b²的值为?
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![若有理数a,b满足(a-b)²+(-3)×(-1)=1-(b+2)²-(-2),则代数式ab+b²的值为?](/uploads/image/z/2661993-9-3.jpg?t=%E8%8B%A5%E6%9C%89%E7%90%86%E6%95%B0a%2Cb%E6%BB%A1%E8%B6%B3%28a-b%29%26%23178%3B%2B%28-3%29%C3%97%28-1%29%3D1-%28b%2B2%29%26%23178%3B-%EF%BC%88-2%EF%BC%89%2C%E5%88%99%E4%BB%A3%E6%95%B0%E5%BC%8Fab%2Bb%26%23178%3B%E7%9A%84%E5%80%BC%E4%B8%BA%3F)
若有理数a,b满足(a-b)²+(-3)×(-1)=1-(b+2)²-(-2),则代数式ab+b²的值为?
若有理数a,b满足(a-b)²+(-3)×(-1)=1-(b+2)²-(-2),则代数式ab+b²的值为?
若有理数a,b满足(a-b)²+(-3)×(-1)=1-(b+2)²-(-2),则代数式ab+b²的值为?
(a-b)²+(-3)×(-1)=1-(b+2)²-(-2),
(a-b)²-(b+2)²+3=1+2
(a-b-b-2)(a-b+b+2)=0
∴a-2b-2=0 a+2=0
a=-2
b=-2
∴ab+b²=(-2)*(-2)+(-2)²=4+4=8