(1/x-y-1/x+y)*x²-2xy+y²/(y+1)²-(y-1)²
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![(1/x-y-1/x+y)*x²-2xy+y²/(y+1)²-(y-1)²](/uploads/image/z/2709951-15-1.jpg?t=%281%2Fx-y-1%2Fx%2By%29%2Ax%26%23178%3B-2xy%2By%26%23178%3B%2F%28y%2B1%29%26%23178%3B-%28y-1%29%26%23178%3B)
(1/x-y-1/x+y)*x²-2xy+y²/(y+1)²-(y-1)²
(1/x-y-1/x+y)*x²-2xy+y²/(y+1)²-(y-1)²
(1/x-y-1/x+y)*x²-2xy+y²/(y+1)²-(y-1)²
原式=(x+y+x-y)/(x+y)(x-y)*(x-y)²/(y+1+y-1)(y+1-y+1)
=2x/(x+y)(x-y)*(x-y)²/4y
=(x²-xy)/(2xy+2y²)