计算:(x+y)的平方-(x-y)的平方能帮我解答一下吗?我要有详细过程的,谢谢!
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![计算:(x+y)的平方-(x-y)的平方能帮我解答一下吗?我要有详细过程的,谢谢!](/uploads/image/z/2994820-52-0.jpg?t=%E8%AE%A1%E7%AE%97%EF%BC%9A%28x%2By%29%E7%9A%84%E5%B9%B3%E6%96%B9-%EF%BC%88x-y%EF%BC%89%E7%9A%84%E5%B9%B3%E6%96%B9%E8%83%BD%E5%B8%AE%E6%88%91%E8%A7%A3%E7%AD%94%E4%B8%80%E4%B8%8B%E5%90%97%3F%E6%88%91%E8%A6%81%E6%9C%89%E8%AF%A6%E7%BB%86%E8%BF%87%E7%A8%8B%E7%9A%84%2C%E8%B0%A2%E8%B0%A2%21)
计算:(x+y)的平方-(x-y)的平方能帮我解答一下吗?我要有详细过程的,谢谢!
计算:(x+y)的平方-(x-y)的平方
能帮我解答一下吗?我要有详细过程的,谢谢!
计算:(x+y)的平方-(x-y)的平方能帮我解答一下吗?我要有详细过程的,谢谢!
(x+y)的平方-(x-y)的平方
=(x+y+x-y)(x+y-x+y)
=2x*2y
=4xy
=x^2+y^2+2xy-x^2-y^2+2xy
=4xy
(x+y)的平方-(x-y)的平方=【(x+y)-(x-y)】【(x+y)+(x-y)】=2y2x=4xy
(x+y)2-(x-y)2
=x2+y2+2xy-(x2+y2-2xy)
=x2+y2+2xy-x2-y2+2xy
=4xy
(x+y)的平方-(x-y)的平方
=x的平方+Y的平方+2XY-(x的平方+Y的平方-2XY)
=x的平方+Y的平方+2XY-x的平方-Y的平方+2XY
=4XY
2 2
(X+Y) — (X-Y)
2 2 2 2
=X +2XY+Y -(X -2XY+Y )
=4XY
(x+y)2-(x-y)2
=x2+y2+2xy-(x2+y2-2xy)
=x2+y2+2xy-x2-y2+2xy
=4xy
(X+Y)*(X+Y)-(X-Y)*(X-Y)
=X*X+2XY+Y*Y-X*X+2XY-Y*Y
=4XY
4xy
计算过程(x+y)2-(x-y)2=x2+2xy+y2-x2+2xy-y2=4xy
这道题其实很简单,(x+y)的平方-(x-y)的平方,首先两数相减去平方,剩下(x+y)-(x-y),此式子去括号化为x+y-x+y,接下来x-x+y+y,结果等于2y。