解方程x²+x-6分之5x+x²-x-12分之2x-5=x²-6x+8分之7x-10
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/03 14:43:41
![解方程x²+x-6分之5x+x²-x-12分之2x-5=x²-6x+8分之7x-10](/uploads/image/z/327644-44-4.jpg?t=%E8%A7%A3%E6%96%B9%E7%A8%8Bx%26%23178%3B%2Bx-6%E5%88%86%E4%B9%8B5x%2Bx%26%23178%3B-x-12%E5%88%86%E4%B9%8B2x-5%3Dx%26%23178%3B-6x%2B8%E5%88%86%E4%B9%8B7x-10)
解方程x²+x-6分之5x+x²-x-12分之2x-5=x²-6x+8分之7x-10
解方程x²+x-6分之5x+x²-x-12分之2x-5=x²-6x+8分之7x-10
解方程x²+x-6分之5x+x²-x-12分之2x-5=x²-6x+8分之7x-10
5x/(x²+x-6)+(2x-5)/(x²-x-12)=(7x-10)/(x²-6x+8)
5x/(x-2)(x+3)+(2x-5)/(x+3)(x-4)=(7x-10)/(x-2)(x-4)
5x(x-4)+(2x-5)(x-2)=(7x-10)(x+3)
5x^2-20x+(2x^2-9x+10)=7x^2+11x-30
7x^2-29x+10=7x^2+11x-30
40x=40
x=1
经检验,x=1是方程的解