设数列{an}和{bn}满足a1=b1=6,a2=b2=4,a3=b3=3 ,且数列{an+1-an}是等差数列,{bn-2}是等比数列(1)求列数{an}和{bn}的通项公=式(2)设{nbn}的前n项和为Sn,求Sn的表达式(3)数列{Cn}满足Cn=an*(bn+2-2),求数列{Cn}的最大
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![设数列{an}和{bn}满足a1=b1=6,a2=b2=4,a3=b3=3 ,且数列{an+1-an}是等差数列,{bn-2}是等比数列(1)求列数{an}和{bn}的通项公=式(2)设{nbn}的前n项和为Sn,求Sn的表达式(3)数列{Cn}满足Cn=an*(bn+2-2),求数列{Cn}的最大](/uploads/image/z/3622976-8-6.jpg?t=%E8%AE%BE%E6%95%B0%E5%88%97%7Ban%7D%E5%92%8C%7Bbn%7D%E6%BB%A1%E8%B6%B3a1%3Db1%3D6%2Ca2%3Db2%3D4%2Ca3%3Db3%3D3+%2C%E4%B8%94%E6%95%B0%E5%88%97%7Ban%2B1-an%7D%E6%98%AF%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%2C%7Bbn-2%7D%E6%98%AF%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%97%281%29%E6%B1%82%E5%88%97%E6%95%B0%7Ban%7D%E5%92%8C%7Bbn%7D%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%3D%E5%BC%8F%282%29%E8%AE%BE%7Bnbn%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C%E4%B8%BASn%2C%E6%B1%82Sn%E7%9A%84%E8%A1%A8%E8%BE%BE%E5%BC%8F%283%29%E6%95%B0%E5%88%97%7BCn%7D%E6%BB%A1%E8%B6%B3Cn%3Dan%2A%28bn%2B2-2%29%2C%E6%B1%82%E6%95%B0%E5%88%97%7BCn%7D%E7%9A%84%E6%9C%80%E5%A4%A7)
设数列{an}和{bn}满足a1=b1=6,a2=b2=4,a3=b3=3 ,且数列{an+1-an}是等差数列,{bn-2}是等比数列(1)求列数{an}和{bn}的通项公=式(2)设{nbn}的前n项和为Sn,求Sn的表达式(3)数列{Cn}满足Cn=an*(bn+2-2),求数列{Cn}的最大
设数列{an}和{bn}满足a1=b1=6,a2=b2=4,a3=b3=3 ,且数列{an+1-an}是等差数列,{bn-2}是等比数列
(1)求列数{an}和{bn}的通项公=式
(2)设{nbn}的前n项和为Sn,求Sn的表达式
(3)数列{Cn}满足Cn=an*(bn+2-2),求数列{Cn}的最大项
设数列{an}和{bn}满足a1=b1=6,a2=b2=4,a3=b3=3 ,且数列{an+1-an}是等差数列,{bn-2}是等比数列(1)求列数{an}和{bn}的通项公=式(2)设{nbn}的前n项和为Sn,求Sn的表达式(3)数列{Cn}满足Cn=an*(bn+2-2),求数列{Cn}的最大
(1)an=(n-6)(n-1)/2+6
bn=2^(3-n)+2
(2) sn=(n-4)*2^(2-n)+n(n+1)+16
(3) cn=[(n-6)(n-1)/2+6]*2^(1-n)
=(n^2-7n+18)/2^n
我只能做到这一步了,接下来得靠楼主自己了
sdggfhgf
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