X2-2X+1-M2≤0(M>0)因式分解如何求解?X2为:X的2次方M2为:M的2次方
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 19:47:44
![X2-2X+1-M2≤0(M>0)因式分解如何求解?X2为:X的2次方M2为:M的2次方](/uploads/image/z/3793242-66-2.jpg?t=X2-2X%2B1-M2%E2%89%A40%28M%EF%BC%9E0%29%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E5%A6%82%E4%BD%95%E6%B1%82%E8%A7%A3%3FX2%E4%B8%BA%EF%BC%9AX%E7%9A%842%E6%AC%A1%E6%96%B9M2%E4%B8%BA%EF%BC%9AM%E7%9A%842%E6%AC%A1%E6%96%B9)
X2-2X+1-M2≤0(M>0)因式分解如何求解?X2为:X的2次方M2为:M的2次方
X2-2X+1-M2≤0(M>0)因式分解如何求解?
X2为:X的2次方
M2为:M的2次方
X2-2X+1-M2≤0(M>0)因式分解如何求解?X2为:X的2次方M2为:M的2次方
x^2-2x+1-M^2
=(x-1)^2-M^2
=(x-1+M)(x-1-M)≤0
∵M>0
所以:
M-1≤x≤M+1
(x-1)²<=M²
X2-2X+1-M2≤0
(X-1)^2-M^2≤0
(X-1-M)(X-1+M)≤0
∵1-M<1+M
∴1-M≤X≤1+M
(x-(1-m))(x-(1+m))