设A={x|2x^2+ax+2=0},B={x|x^2+3x+2a=0},A∪B={0.5,-5,2},求A∩B
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![设A={x|2x^2+ax+2=0},B={x|x^2+3x+2a=0},A∪B={0.5,-5,2},求A∩B](/uploads/image/z/3799169-17-9.jpg?t=%E8%AE%BEA%3D%7Bx%7C2x%5E2%2Bax%2B2%3D0%7D%2CB%3D%7Bx%7Cx%5E2%2B3x%2B2a%3D0%7D%2CA%E2%88%AAB%3D%7B0.5%2C-5%2C2%7D%2C%E6%B1%82A%E2%88%A9B)
设A={x|2x^2+ax+2=0},B={x|x^2+3x+2a=0},A∪B={0.5,-5,2},求A∩B
设A={x|2x^2+ax+2=0},B={x|x^2+3x+2a=0},A∪B={0.5,-5,2},求A∩B
设A={x|2x^2+ax+2=0},B={x|x^2+3x+2a=0},A∪B={0.5,-5,2},求A∩B
2x^2+ax+2=0的根x1,x2属于{0.5,-5,2},
因为:x1*x2=2/2=1
所以,x1,x2分别为0.5,2
A={0.5,2}
x^2+3x+2a=0根x1,x2属于{0.5,-5,2},
因为:x1+x2=-3
所以,x1,x2分别为-5,2
B={-5,2}
A∩B={2}
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