设A={x|2x^2+ax+2=0} B={x|x^2+3x+2a=0} 且A交B={2}求a的值 集合A B
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 01:09:05
![设A={x|2x^2+ax+2=0} B={x|x^2+3x+2a=0} 且A交B={2}求a的值 集合A B](/uploads/image/z/3799171-19-1.jpg?t=%E8%AE%BEA%3D%7Bx%7C2x%5E2%2Bax%2B2%3D0%7D+B%3D%7Bx%7Cx%5E2%2B3x%2B2a%3D0%7D+%E4%B8%94A%E4%BA%A4B%3D%7B2%7D%E6%B1%82a%E7%9A%84%E5%80%BC+%E9%9B%86%E5%90%88A+B)
设A={x|2x^2+ax+2=0} B={x|x^2+3x+2a=0} 且A交B={2}求a的值 集合A B
设A={x|2x^2+ax+2=0} B={x|x^2+3x+2a=0} 且A交B={2}
求a的值 集合A B
设A={x|2x^2+ax+2=0} B={x|x^2+3x+2a=0} 且A交B={2}求a的值 集合A B
解;代入有:8+2a+2=0.a=-5 A={0.5,2},B={-5,2}
设集合A={x/x^2-3x-4>0},B={x/x^2-ax+b
设f(x)=x^2+ax+b,且0
线性代数2,设AX+B=X
设集合A={x|2x^2-ax+b=0},B={x|x^2+6x+8,x∈R},求A∩B
设lim(x->无穷大)((1+x^2+x^3)^1/3-ax-b)=0,求a= ,b= .
设lim((x^2+1)/(x+1) -ax-b)=0,求a,b.x趋向无穷大
设lim((x^2+1)/(x+1) -ax-b)=0,求a,b. x趋向无穷大
设不等式x^2-ax-8>=0与x^2-2ax-b
设lim[(x^2+2x+3)^1/2-ax]=b,求a,b
f(x)=Inx-ax^2+2x-ax 设a>0 证明 当0
设集合A={x|x^2-2ax+3
设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
设集合A={x|log1/2(6+x-x^2)>-2},B={x|根号下ax-a^2|