已知函数f(x)=Asin(4x+φ)(A>0,0<φ<π)在x=π/16时取得最大值2(1)求f(x)的最小正周期(2)求f(x)的解析式(3)若α∈[-π/2,0],f(1/4α+π/16)=6/5,求sin(2α-π/4)的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/02 03:36:26
![已知函数f(x)=Asin(4x+φ)(A>0,0<φ<π)在x=π/16时取得最大值2(1)求f(x)的最小正周期(2)求f(x)的解析式(3)若α∈[-π/2,0],f(1/4α+π/16)=6/5,求sin(2α-π/4)的值](/uploads/image/z/3801985-25-5.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3DAsin%284x%2B%CF%86%29%28A%26gt%3B0%2C0%26lt%3B%CF%86%26lt%3B%CF%80%29%E5%9C%A8x%3D%CF%80%2F16%E6%97%B6%E5%8F%96%E5%BE%97%E6%9C%80%E5%A4%A7%E5%80%BC2%281%29%E6%B1%82f%28x%29%E7%9A%84%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%282%29%E6%B1%82f%28x%29%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%283%29%E8%8B%A5%CE%B1%E2%88%88%5B-%CF%80%2F2%2C0%5D%2Cf%281%2F4%CE%B1%2B%CF%80%2F16%29%3D6%2F5%2C%E6%B1%82sin%282%CE%B1-%CF%80%2F4%29%E7%9A%84%E5%80%BC)
已知函数f(x)=Asin(4x+φ)(A>0,0<φ<π)在x=π/16时取得最大值2(1)求f(x)的最小正周期(2)求f(x)的解析式(3)若α∈[-π/2,0],f(1/4α+π/16)=6/5,求sin(2α-π/4)的值
已知函数f(x)=Asin(4x+φ)(A>0,0<φ<π)在x=π/16时取得最大值2
(1)求f(x)的最小正周期
(2)求f(x)的解析式
(3)若α∈[-π/2,0],f(1/4α+π/16)=6/5,求sin(2α-π/4)的值
已知函数f(x)=Asin(4x+φ)(A>0,0<φ<π)在x=π/16时取得最大值2(1)求f(x)的最小正周期(2)求f(x)的解析式(3)若α∈[-π/2,0],f(1/4α+π/16)=6/5,求sin(2α-π/4)的值
∵f(x)=Asin(4x+φ)(A>0,0
已知函数f(x)=Asin(ωx+φ)
已知函数f(x)=Asin
已知函数f(x)=Asin(x+&)(A>0,0
已知函数f[x]=Asin²【ωx+
已知函数f(x)=Asin(x+q) (0
已知函数f(x)=Asin(2x+φ) (A>0,0已知函数f(x)=Asin(2x+φ) (A>0,0
已知函数f(x)=Asin(wx+φ)图像如图 求f(x)
已知函数f(x)=Asin(3x +φ),(A>0,x∈(-∞,+∞),0
已知函数f(x)=Asin(3x +φ),(A>0,x∈(-∞,+∞),0
已知函数f(x)=Asin(2ωx+φ)(x∈R,ω>0,0
已知函数f(x)=Asin(2x+φ),当x=-π/3时,最小值为-4,
已知函数f(x)=Asin(wx+φ)(A
已知函数f(x)=Asin(ωx+φ)(A>0,|φ|0,|φ|
已知函数f (x)=Asin(ωx=φ)(A>0,ω>0,|φ|
已知函数f(x)=Asin(ωx+φ)+B(A>0,ω>0,|φ|
已知函数f(x)=Asin(ωx+φ)(A>0,ω>0,|φ|
已知函数f(x)=Asin(ωx+φ)(A>0,ω>0,|φ|
已知函数f(x)=Asin(ωx+φ)(A>0,ω>0,|φ|