如果2/(x-2)+m/(x^2-4)=3/(x+2)有增根,m=?
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![如果2/(x-2)+m/(x^2-4)=3/(x+2)有增根,m=?](/uploads/image/z/3820303-55-3.jpg?t=%E5%A6%82%E6%9E%9C2%2F%28x-2%29%2Bm%2F%28x%5E2-4%29%3D3%2F%28x%2B2%29%E6%9C%89%E5%A2%9E%E6%A0%B9%2Cm%3D%3F)
如果2/(x-2)+m/(x^2-4)=3/(x+2)有增根,m=?
如果2/(x-2)+m/(x^2-4)=3/(x+2)有增根,m=?
如果2/(x-2)+m/(x^2-4)=3/(x+2)有增根,m=?
∵2/(x-2)+m/(x²-4)=3/(x+2)
==>2(x+2)+m=3(x-2)
==>2x+4+m=3x-6
==>x=m+10
∴x=m+10
∵原方程有增根
∴增根是x=±2 (∵原方程的分母是x²-4)
∴m+10=±2
故m=-8,或m=-12