已知|6-3m|+(n-5)²=3m-6-√[(m-3)n²]则m-n=
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![已知|6-3m|+(n-5)²=3m-6-√[(m-3)n²]则m-n=](/uploads/image/z/4100025-57-5.jpg?t=%E5%B7%B2%E7%9F%A5%7C6-3m%7C%2B%EF%BC%88n-5%EF%BC%89%26%23178%3B%3D3m-6-%E2%88%9A%5B%EF%BC%88m-3%EF%BC%89n%26%23178%3B%5D%E5%88%99m-n%3D)
已知|6-3m|+(n-5)²=3m-6-√[(m-3)n²]则m-n=
已知|6-3m|+(n-5)²=3m-6-√[(m-3)n²]则m-n=
已知|6-3m|+(n-5)²=3m-6-√[(m-3)n²]则m-n=
∵|6-3m|+(n-5)2=3m-6-
∴6-3m<0,
∴m>2,
∴n-5=0,
n=5,
∴m-3=0,
m=3,
则m-n=3-5=-2.
故答案为:-2.