已知根号下(x²-2x+1)+根号下(x²-10x+25)=4,化简根号下(2x-2)².+x-5的绝对值
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![已知根号下(x²-2x+1)+根号下(x²-10x+25)=4,化简根号下(2x-2)².+x-5的绝对值](/uploads/image/z/4331536-16-6.jpg?t=%E5%B7%B2%E7%9F%A5%E6%A0%B9%E5%8F%B7%E4%B8%8B%28x%26%23178%3B-2x%2B1%29%2B%E6%A0%B9%E5%8F%B7%E4%B8%8B%28x%26%23178%3B-10x%2B25%29%3D4%2C%E5%8C%96%E7%AE%80%E6%A0%B9%E5%8F%B7%E4%B8%8B%282x-2%EF%BC%89%26%23178%3B.%2Bx-5%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC)
已知根号下(x²-2x+1)+根号下(x²-10x+25)=4,化简根号下(2x-2)².+x-5的绝对值
已知根号下(x²-2x+1)+根号下(x²-10x+25)=4,化简根号下(2x-2)².+x-5的绝对值
已知根号下(x²-2x+1)+根号下(x²-10x+25)=4,化简根号下(2x-2)².+x-5的绝对值
∵√(x²-2x+1)+√(x²-10x+25)=4
即|x-1|+|x-5|=4
∴1≤x≤5
∴2x-2≥0,x-5≤0
∴√(2x-2)².+|x-5|
=2x-2+5-x
=x+3