g=a^x求证:g[(x1+x2)/2]小于等于[g(x1)+g(x2)]/2a>0,a不得于1...
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/29 22:33:57
![g=a^x求证:g[(x1+x2)/2]小于等于[g(x1)+g(x2)]/2a>0,a不得于1...](/uploads/image/z/5158356-60-6.jpg?t=g%3Da%5Ex%E6%B1%82%E8%AF%81%EF%BC%9Ag%5B%28x1%2Bx2%29%2F2%5D%E5%B0%8F%E4%BA%8E%E7%AD%89%E4%BA%8E%5Bg%28x1%29%2Bg%28x2%29%5D%2F2a%3E0%2Ca%E4%B8%8D%E5%BE%97%E4%BA%8E1...)
g=a^x求证:g[(x1+x2)/2]小于等于[g(x1)+g(x2)]/2a>0,a不得于1...
g=a^x
求证:
g[(x1+x2)/2]小于等于[g(x1)+g(x2)]/2
a>0,a不得于1...
g=a^x求证:g[(x1+x2)/2]小于等于[g(x1)+g(x2)]/2a>0,a不得于1...
给分吧,