tana=1,tanb=4,tan(2a-b)=
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![tana=1,tanb=4,tan(2a-b)=](/uploads/image/z/5192357-5-7.jpg?t=tana%3D1%2Ctanb%3D4%2Ctan%282a-b%29%3D)
tana=1,tanb=4,tan(2a-b)=
tana=1,tanb=4,tan(2a-b)=
tana=1,tanb=4,tan(2a-b)=
tanα=1,tanβ=4,求tan(2α-β)=?
∵tanα=1,∴α=π/4+kπ,2α=π/2+2kπ.
∴tan(2α-β)=tan(π/2+2kπ-β)=tan(π/2-β)=cotβ=1/tanβ=1/4