真么写已知如图ab=ac ad=ae ab dc相交于点m ac be相交于点n,角bab=角eac 求角am=an已知如图ab=ac ad=ae ab dc相交于点m ac be相交于点n,角bab=角eac求角am=an
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 03:54:40
![真么写已知如图ab=ac ad=ae ab dc相交于点m ac be相交于点n,角bab=角eac 求角am=an已知如图ab=ac ad=ae ab dc相交于点m ac be相交于点n,角bab=角eac求角am=an](/uploads/image/z/5236026-42-6.jpg?t=%E7%9C%9F%E4%B9%88%E5%86%99%E5%B7%B2%E7%9F%A5%E5%A6%82%E5%9B%BEab%3Dac+ad%3Dae+ab+dc%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9m+ac+be%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9n%2C%E8%A7%92bab%3D%E8%A7%92eac+%E6%B1%82%E8%A7%92am%3Dan%E5%B7%B2%E7%9F%A5%E5%A6%82%E5%9B%BEab%3Dac+ad%3Dae+ab++dc%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9m+ac+be%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9n%2C%E8%A7%92bab%3D%E8%A7%92eac%E6%B1%82%E8%A7%92am%3Dan)
真么写已知如图ab=ac ad=ae ab dc相交于点m ac be相交于点n,角bab=角eac 求角am=an已知如图ab=ac ad=ae ab dc相交于点m ac be相交于点n,角bab=角eac求角am=an
真么写已知如图ab=ac ad=ae ab dc相交于点m ac be相交于点n,角bab=角eac 求角am=an已知如图ab=ac ad=ae ab dc相交于点m ac be相交于点n,角bab=角eac
求角am=an
真么写已知如图ab=ac ad=ae ab dc相交于点m ac be相交于点n,角bab=角eac 求角am=an已知如图ab=ac ad=ae ab dc相交于点m ac be相交于点n,角bab=角eac求角am=an
证明:∵AB=AC,AD=AE,∠DAB=∠EAC,
∴∠DAC=∠AEB,
∴△ACD≌△ABE,
∴∠D=∠E,
又AD=AE,∠DAB=∠EAC,
∴△ADM≌△AEN.
am=an
30度
角bab=角eac这个是什么条件呀
◆题目表达不太清楚,在此设AB交CE于M,AC交BD于N.
证明:∵AB=AC;AD=AE;∠DAB=∠EAC.
∴⊿DAB≌⊿EAC(SAS),∠D=∠E.
∵∠DAB=∠EAC.
∴∠DAB-∠BAC=∠EAC-∠BAC,即∠DAN=∠EAM.
∵∠D=∠E(已证);AD=AE(已知);∠DAN=∠EAM(已证).
∴⊿DAN≌⊿EAM(AAS),AM=AN.
证明:∵AB=AC,AD=AE,∠DAB=∠EAC,
∴∠DAC=∠AEB,
∴△ACD≌△ABE,
∴∠D=∠E,
又AD=AE,∠DAB=∠EAC,
∴△ADM≌△AEN.
AM=AN