f(x)=x²-ax+5在[1,+∞)上为增函数,在(-∞,1]上为减函数,求f(2),f(3)
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![f(x)=x²-ax+5在[1,+∞)上为增函数,在(-∞,1]上为减函数,求f(2),f(3)](/uploads/image/z/5569294-22-4.jpg?t=f%28x%29%3Dx%26%23178%3B-ax%2B5%E5%9C%A8%5B1%2C%2B%E2%88%9E%EF%BC%89%E4%B8%8A%E4%B8%BA%E5%A2%9E%E5%87%BD%E6%95%B0%2C%E5%9C%A8%EF%BC%88-%E2%88%9E%2C1%5D%E4%B8%8A%E4%B8%BA%E5%87%8F%E5%87%BD%E6%95%B0%2C%E6%B1%82f%EF%BC%882%EF%BC%89%2Cf%EF%BC%883%EF%BC%89)
f(x)=x²-ax+5在[1,+∞)上为增函数,在(-∞,1]上为减函数,求f(2),f(3)
f(x)=x²-ax+5在[1,+∞)上为增函数,在(-∞,1]上为减函数,求f(2),f(3)
f(x)=x²-ax+5在[1,+∞)上为增函数,在(-∞,1]上为减函数,求f(2),f(3)
1=a/2 , a=2
f(x)=x²-ax+5=x²-2x+5 , f(2)=5 , f(3)=8