若a²+3a+1=0,a四次方+3a³-a²-5a+a分之1-2求a四次方+3a³-a²-5a+a分之1-2
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若a²+3a+1=0,a四次方+3a³-a²-5a+a分之1-2求a四次方+3a³-a²-5a+a分之1-2
若a²+3a+1=0,a四次方+3a³-a²-5a+a分之1-2
求
a四次方+3a³-a²-5a+a分之1-2
若a²+3a+1=0,a四次方+3a³-a²-5a+a分之1-2求a四次方+3a³-a²-5a+a分之1-2
= a4 +3a³+ a²-2a²-5a+1/a -2=a2(a²+3a+1)-2(a²+3a+1)+a+1/a-2= a2×0-2×0+a+1/a-2= a+1/a -2
= (a²+1)/a -2因为a²+3a+1=0,所以a²+1=-3a,代入上式得:(a²+1)/a -2=-3a/a -2
=-3-2
=-5