6.在△ABC中,AB=AC,BD平分∠ABC交AC于D,DE垂直平分AB,垂足为E,则∠C= .
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![6.在△ABC中,AB=AC,BD平分∠ABC交AC于D,DE垂直平分AB,垂足为E,则∠C= .](/uploads/image/z/698418-18-8.jpg?t=%26%23160%3B6%EF%BC%8E%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2CAB%EF%BC%9DAC%2CBD%E5%B9%B3%E5%88%86%E2%88%A0ABC%E4%BA%A4AC%E4%BA%8ED%2CDE%E5%9E%82%E7%9B%B4%E5%B9%B3%E5%88%86AB%2C%E5%9E%82%E8%B6%B3%E4%B8%BAE%2C%E5%88%99%E2%88%A0C%EF%BC%9D%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B+.)
6.在△ABC中,AB=AC,BD平分∠ABC交AC于D,DE垂直平分AB,垂足为E,则∠C= .
6.在△ABC中,AB=AC,BD平分∠ABC交AC于D,DE垂直平分AB,垂足为E,则∠C= .
6.在△ABC中,AB=AC,BD平分∠ABC交AC于D,DE垂直平分AB,垂足为E,则∠C= .
∠C=72°
因为DE垂直平分AB,所以∠A=∠ABD,
因为BD平分∠ABC,所以∠ABD=∠CBD,所以∠A=1/2∠ABC
因为AB=AC,所以∠ABC=∠C
所以∠C=2∠A
所以∠A+∠ABC+∠C=180°
∠A=36°
∠C=2∠A=72°
m没图吗
∵AB=AC
∴∠ABC=∠C
∵DE垂直平分AB
∴DA=DB
∴∠A=∠ABD
∵BD平分∠ABC
∴∠ABC=2∠A
∵∠A+∠ABC+∠C=180°
∴5∠A=180°
∴∠A=36°
36
36度