f(x)=9*/9*+3,则f(1/2004)+f(2/2004)+.+f(2002/2004)+f(2003/2004)=?*=x次方
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![f(x)=9*/9*+3,则f(1/2004)+f(2/2004)+.+f(2002/2004)+f(2003/2004)=?*=x次方](/uploads/image/z/9940295-47-5.jpg?t=f%28x%29%3D9%2A%2F9%2A%2B3%2C%E5%88%99f%281%2F2004%29%2Bf%282%2F2004%29%2B.%2Bf%282002%2F2004%29%2Bf%282003%2F2004%29%3D%3F%2A%3Dx%E6%AC%A1%E6%96%B9)
f(x)=9*/9*+3,则f(1/2004)+f(2/2004)+.+f(2002/2004)+f(2003/2004)=?*=x次方
f(x)=9*/9*+3,则f(1/2004)+f(2/2004)+.+f(2002/2004)+f(2003/2004)=?*=x次方
f(x)=9*/9*+3,则f(1/2004)+f(2/2004)+.+f(2002/2004)+f(2003/2004)=?*=x次方
可以计算出f(k/2004)+f(2004-k/2004)=3,这个你通分计算就可以得到.那么所求代数式的值为1001*3+3/2=3004.5,其中f(2002/2004)=3/2