.根据下列条件解三角形:(1)已知A=30°,B=45°,a =10,求b,c,C.(2)已知A=75°,a=10,c=8,求b,B,C.(3)已知B=120°,b= 5,c= 10,求a,A,C.(4)已知c=30°,b=10,c=5根号2,求a,A,B.(5)已知a=12,b =5,c =10,求A,B,C.(6)已知b=5,c =10,A =60°,求
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![.根据下列条件解三角形:(1)已知A=30°,B=45°,a =10,求b,c,C.(2)已知A=75°,a=10,c=8,求b,B,C.(3)已知B=120°,b= 5,c= 10,求a,A,C.(4)已知c=30°,b=10,c=5根号2,求a,A,B.(5)已知a=12,b =5,c =10,求A,B,C.(6)已知b=5,c =10,A =60°,求](/uploads/image/z/10257095-47-5.jpg?t=%EF%BC%8E%E6%A0%B9%E6%8D%AE%E4%B8%8B%E5%88%97%E6%9D%A1%E4%BB%B6%E8%A7%A3%E4%B8%89%E8%A7%92%E5%BD%A2%EF%BC%9A%281%29%E5%B7%B2%E7%9F%A5A%3D30%C2%B0%2CB%3D45%C2%B0%2Ca+%3D10%2C%E6%B1%82b%2Cc%2CC.%282%29%E5%B7%B2%E7%9F%A5A%3D75%C2%B0%2Ca%3D10%2Cc%3D8%2C%E6%B1%82b%2CB%2CC.%283%29%E5%B7%B2%E7%9F%A5B%3D120%C2%B0%2Cb%3D+5%2Cc%3D+10%2C%E6%B1%82a%2CA%2CC.%284%29%E5%B7%B2%E7%9F%A5c%3D30%C2%B0%2Cb%3D10%2Cc%3D5%E6%A0%B9%E5%8F%B72%2C%E6%B1%82a%2CA%2CB.%285%29%E5%B7%B2%E7%9F%A5a%3D12%2Cb+%3D5%2Cc+%3D10%2C%E6%B1%82A%2CB%2CC.%286%29%E5%B7%B2%E7%9F%A5b%3D5%2Cc+%3D10%2CA+%3D60%C2%B0%2C%E6%B1%82)
.根据下列条件解三角形:(1)已知A=30°,B=45°,a =10,求b,c,C.(2)已知A=75°,a=10,c=8,求b,B,C.(3)已知B=120°,b= 5,c= 10,求a,A,C.(4)已知c=30°,b=10,c=5根号2,求a,A,B.(5)已知a=12,b =5,c =10,求A,B,C.(6)已知b=5,c =10,A =60°,求
.根据下列条件解三角形:
(1)已知A=30°,B
=45°,a =10,求b,c,C.
(2)已知A=75°,a=10,c=8,求b,B,C.
(3)已知B=120°,b= 5,c= 10,求a,A,C.
(4)已知c=30°,b=10,c=5根号2,求a,A,B.
(5)已知a=12,b =5,c =10,求A,B,C.
(6)已知b=5,c =10,A =60°,求a.B.C
.根据下列条件解三角形:(1)已知A=30°,B=45°,a =10,求b,c,C.(2)已知A=75°,a=10,c=8,求b,B,C.(3)已知B=120°,b= 5,c= 10,求a,A,C.(4)已知c=30°,b=10,c=5根号2,求a,A,B.(5)已知a=12,b =5,c =10,求A,B,C.(6)已知b=5,c =10,A =60°,求
跟据a/sina=b/sinb=c/sinc可知第1问b=10根号2.c边=5(根号6+根号2).c角=180-30-45=105.下面几问由此类推
你好懒惰啊!用正弦定理解吧!详细的我给你不解
这是高中三角函数练习题,你是高中生的话应该自己做,做了才能掌握知识,靠百度找人代答对你的学习没有半点帮助的,希珍重学业。
画图,用正余弦定理那两个公式求。知道答案没用,掌握了才行,最好自己做。多练!