把下列多项式因式分解(x+1)(x+2)(x+3)(x+4)-24 3a²b²-17abxy+10x²y² (x²-2x)²-7(x²-2x)+12 a(a+m)-b(b+m) (x²+2x+2)(x²+2x-3)+4
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/02 01:14:35
![把下列多项式因式分解(x+1)(x+2)(x+3)(x+4)-24 3a²b²-17abxy+10x²y² (x²-2x)²-7(x²-2x)+12 a(a+m)-b(b+m) (x²+2x+2)(x²+2x-3)+4](/uploads/image/z/1239747-51-7.jpg?t=%E6%8A%8A%E4%B8%8B%E5%88%97%E5%A4%9A%E9%A1%B9%E5%BC%8F%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%28x%2B1%29%28x%2B2%29%28x%2B3%29%28x%2B4%29-24+3a%26sup2%3Bb%26sup2%3B-17abxy%2B10x%26sup2%3By%26sup2%3B+%28x%26sup2%3B-2x%29%26sup2%3B-7%28x%26sup2%3B-2x%29%2B12+a%28a%2Bm%29-b%28b%2Bm%29+%28x%26sup2%3B%2B2x%2B2%29%28x%26sup2%3B%2B2x-3%29%2B4)
把下列多项式因式分解(x+1)(x+2)(x+3)(x+4)-24 3a²b²-17abxy+10x²y² (x²-2x)²-7(x²-2x)+12 a(a+m)-b(b+m) (x²+2x+2)(x²+2x-3)+4
把下列多项式因式分解
(x+1)(x+2)(x+3)(x+4)-24 3a²b²-17abxy+10x²y² (x²-2x)²-7(x²-2x)+12 a(a+m)-b(b+m) (x²+2x+2)(x²+2x-3)+4
把下列多项式因式分解(x+1)(x+2)(x+3)(x+4)-24 3a²b²-17abxy+10x²y² (x²-2x)²-7(x²-2x)+12 a(a+m)-b(b+m) (x²+2x+2)(x²+2x-3)+4
(x+1)(x+2)(x+3)(x+4)-24
=[(x+1)(x+4)][(x+2)(x+3)]-24
=(x^2+5x+4)(x^2+5x+6)-24
=(x^2+5x+4)^2+2(x^2+5x+4)-24
=(x^2+5x+4+6)(x^2+5x+4-4)
=(x^2+5x+10)(x^2+5x)
=x(x+5)(x^2+5x+10)
3a²b²-17abxy+10x²y²
=(3ab-2xy)(ab-5xy)
(x²-2x)²-7(x²-2x)+12
=(x^2-2x-3)(x^2-2x-4)
=(x-3)(x+1)(x^2-2x-4)
a(a+m)-b(b+m)
=a^2+am-b^2-bm
=a^2-b^2+am-bm
=(a^2-b^2)+m(a-b)
=(a+b)(a-b)+m(a-b)
=(a+b)(a-b+m)
(x²+2x+2)(x²+2x-3)+4
=(x^2+2x)^2-(x^2+2x)-2
=(x^2+2x-2)(x^2+2x+1)
=(x^2+2x-2)(x+1)^2
1)(x+1)(x+2)(x+3)(x+4)-24
=(x+1)(x+4)(x+2)(x+3)-24
=(x^2+5x+4)(x^2+5x+6)-24
=(x^2+5x)^2+10(x^2+5x)+24-24
=(x^2+5x)(x^2+5x+10)
=x(x+5)(x^2+5x+10)
2)3a^2b^2-17abxy+10x^...
全部展开
1)(x+1)(x+2)(x+3)(x+4)-24
=(x+1)(x+4)(x+2)(x+3)-24
=(x^2+5x+4)(x^2+5x+6)-24
=(x^2+5x)^2+10(x^2+5x)+24-24
=(x^2+5x)(x^2+5x+10)
=x(x+5)(x^2+5x+10)
2)3a^2b^2-17abxy+10x^2y^2
=(3ab-2xy)(ab-5xy)
3)(x^2-2x)^2-7(x^2-2x)+12
=(x^2-2x-3)(x^2-2x-4)
=(x+1)(x-3)(x^2-2x-4)
4)a(a+m)-b(b+m)
=a^2+am-b^2-bm
=(a+b)(a-b)+m(a-b)
=(a-b)(a+b+m)
5)(x^2+2x+2)(x^2+2x-3)+4
=(x^2+2x)^2-(x^2+2x)-6+4
=(x^2+2x)^2-(x^2+2x)-2
=(x^2+2x+1)(x^2+2x-2)
=(x+1)^2(x^2+2x-2)
收起