若多项式(2x的2次方+ax-y+6)-(2bx的2次方-3x+5y-1)的值与字母x所取的值无关= ( 2x^2 - 2bx^2 ) + ( ax + 3x )-( y + 5y )+( 6 + 1 )= 2x^2( 1 - b ) + ( a + 3 )x - 6y + 72x^2 - 2bx^2 ) 怎么变成2x^2( 1 - b )
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![若多项式(2x的2次方+ax-y+6)-(2bx的2次方-3x+5y-1)的值与字母x所取的值无关= ( 2x^2 - 2bx^2 ) + ( ax + 3x )-( y + 5y )+( 6 + 1 )= 2x^2( 1 - b ) + ( a + 3 )x - 6y + 72x^2 - 2bx^2 ) 怎么变成2x^2( 1 - b )](/uploads/image/z/1613648-56-8.jpg?t=%E8%8B%A5%E5%A4%9A%E9%A1%B9%E5%BC%8F%EF%BC%882x%E7%9A%842%E6%AC%A1%E6%96%B9%2Bax-y%2B6%EF%BC%89-%EF%BC%882bx%E7%9A%842%E6%AC%A1%E6%96%B9-3x%2B5y-1%EF%BC%89%E7%9A%84%E5%80%BC%E4%B8%8E%E5%AD%97%E6%AF%8Dx%E6%89%80%E5%8F%96%E7%9A%84%E5%80%BC%E6%97%A0%E5%85%B3%3D+%28+2x%5E2+-+2bx%5E2+%29+%2B+%28+ax+%2B+3x+%29-%28+y+%2B+5y+%29%2B%28+6+%2B+1+%29%3D+2x%5E2%28+1+-+b+%29+%2B+%28+a+%2B+3+%29x+-+6y+%2B+72x%5E2+-+2bx%5E2+%29+%E6%80%8E%E4%B9%88%E5%8F%98%E6%88%902x%5E2%28+1+-+b+%29)
若多项式(2x的2次方+ax-y+6)-(2bx的2次方-3x+5y-1)的值与字母x所取的值无关= ( 2x^2 - 2bx^2 ) + ( ax + 3x )-( y + 5y )+( 6 + 1 )= 2x^2( 1 - b ) + ( a + 3 )x - 6y + 72x^2 - 2bx^2 ) 怎么变成2x^2( 1 - b )
若多项式(2x的2次方+ax-y+6)-(2bx的2次方-3x+5y-1)的值与字母x所取的值无关
= ( 2x^2 - 2bx^2 ) + ( ax + 3x )-( y + 5y )+( 6 + 1 )
= 2x^2( 1 - b ) + ( a + 3 )x - 6y + 7
2x^2 - 2bx^2 ) 怎么变成2x^2( 1 - b )
若多项式(2x的2次方+ax-y+6)-(2bx的2次方-3x+5y-1)的值与字母x所取的值无关= ( 2x^2 - 2bx^2 ) + ( ax + 3x )-( y + 5y )+( 6 + 1 )= 2x^2( 1 - b ) + ( a + 3 )x - 6y + 72x^2 - 2bx^2 ) 怎么变成2x^2( 1 - b )
(2x的2次方+ax-y+6)-(2bx的2次方-3x+5y-1)
= ( 2x^2 - 2bx^2 ) + ( ax + 3x )-( y + 5y )+( 6 + 1 )
= 2x^2( 1 - b ) + ( a + 3 )x - 6y + 7 ( 提取公因式 2x^2、x )
由于,多项式(2x的2次方+ax-y+6)-(2bx的2次方-3x+5y-1)的值与字母x所取的值无关
则 1 - b = 0 ,a + 3 = 0
所以 b = 1 ,a = -3
提公因式2x^2后得到的2x^2( 1 - b )