设函数f(x)=sin (2x+φ),(-π
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设函数f(x)=sin (2x+φ),(-π
设函数f(x)=sin (2x+φ),(-π<φ<0),y=(x)图像的一条对称轴是直线x=8/π,求函数f(x)的单调递增区间.
设函数f(x)=sin (2x+φ),(-π
(π/8+kπ,5π/8+kπ) ,先根据对称轴求出ψ,然后在计算单调区间.
(π/8+kπ,5π/8+kπ)
(π/8+kπ,5π/8+kπ) ,先根据对称轴求出ψ,然后再计算单调区间。
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