需要原理及过程,我不仅想知道过程更想知道怎么做1)(a²-3a+2)x²+(2a²-4a+1)xy+(a²-a)y²2)3x²y²-17mnxy+10m²n²3)x²+4y²+9z²-4xy-12yz+6xz4)(a²-3a+2)x²+(2a²-4a+1)x
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 12:16:35
![需要原理及过程,我不仅想知道过程更想知道怎么做1)(a²-3a+2)x²+(2a²-4a+1)xy+(a²-a)y²2)3x²y²-17mnxy+10m²n²3)x²+4y²+9z²-4xy-12yz+6xz4)(a²-3a+2)x²+(2a²-4a+1)x](/uploads/image/z/2689681-49-1.jpg?t=%E9%9C%80%E8%A6%81%E5%8E%9F%E7%90%86%E5%8F%8A%E8%BF%87%E7%A8%8B%2C%E6%88%91%E4%B8%8D%E4%BB%85%E6%83%B3%E7%9F%A5%E9%81%93%E8%BF%87%E7%A8%8B%E6%9B%B4%E6%83%B3%E7%9F%A5%E9%81%93%E6%80%8E%E4%B9%88%E5%81%9A1%29%28a%26sup2%3B-3a%2B2%29x%26sup2%3B%2B%282a%26sup2%3B-4a%2B1%29xy%2B%28a%26sup2%3B-a%29y%26sup2%3B2%EF%BC%893x%26sup2%3By%26sup2%3B-17mnxy%2B10m%26sup2%3Bn%26sup2%3B3%29x%26sup2%3B%2B4y%26sup2%3B%2B9z%26sup2%3B-4xy-12yz%2B6xz4%29%28a%26sup2%3B-3a%2B2%29x%26sup2%3B%2B%282a%26sup2%3B-4a%2B1%29x)
需要原理及过程,我不仅想知道过程更想知道怎么做1)(a²-3a+2)x²+(2a²-4a+1)xy+(a²-a)y²2)3x²y²-17mnxy+10m²n²3)x²+4y²+9z²-4xy-12yz+6xz4)(a²-3a+2)x²+(2a²-4a+1)x
需要原理及过程,我不仅想知道过程更想知道怎么做
1)(a²-3a+2)x²+(2a²-4a+1)xy+(a²-a)y²
2)3x²y²-17mnxy+10m²n²
3)x²+4y²+9z²-4xy-12yz+6xz
4)(a²-3a+2)x²+(2a²-4a+1)xy+(a²-a)y²
5)-2xˆ5n-1yˆn+4xˆ3n-1yˆn+2-2xˆn-1yˆn+4
有一题打错了,补上:
4)a²-b²-ac+四分之一c²
需要原理及过程,我不仅想知道过程更想知道怎么做1)(a²-3a+2)x²+(2a²-4a+1)xy+(a²-a)y²2)3x²y²-17mnxy+10m²n²3)x²+4y²+9z²-4xy-12yz+6xz4)(a²-3a+2)x²+(2a²-4a+1)x
1)(a^2-3a+2)x^2+(2a^2-4a+1)xy+(a^2-a)y^2
=(a-1)(a-2)x^2+(2a^2-4a+1)x+a(a-1)y^2
=[(a-1)x+ay][(a-2)x+(a-1)y]
2)3x^2y^2 -17mnxy+10m^2n^2
=(3xy-2mn)(xy-5mn)
3)x^2+4y^2+9z^2-4xy-12yz+6xz
=(x-2y)^2+6z(x-2y)+9z^2
=(x-2y+3z)^2
4)a2-b2-ac+c2/4
=(a-c/2)^2-b^2
=(a+b-c/2)(a-b-c/2)
5)-2x?5n*y?n+4x?3n*y?n+2-2x?n*y?n+4
=-2x^ny^n(x^4n-2x^2ny^2+y^4)
=-2x^ny^n(x^2n-y^2)^2
1.十字相乘法
2.公式法
3.分组分解法
4.主元法:
5.构造法
6.换元法
1) =(a-1)(a-2)x^2+(2a^2-4a+1)xy+a(a-1)y^2=[(a-1)x+(a+2)y][ax+(a-1)y]
2)= 3(xy)^2-17(mn)(xy)+10(mn)^2=(3xy-2)(xy-5)
3)=(x-2y)^2+6z(x-2y)+9z^2=(x-2y+3z)^2
4)同上
5)题目写清楚点,这个有很大歧义
你的第一题是不是抄错了,应该是2a²-3a+1吧
3)(x-2y-3z)的平方
其它的还没想出来,你从那找的
1)=(a-1)(a-2)x^2+(2a^2-4a+1)x+a(a-1)y^2
=[(a-1)x+ay][(a-2)x+(a-1)y]
2) =(3xy-2mn)(xy-5mn)
3)=(x-2y)^2+6z(x-2y)+9z^2
=(x-2y+3z)^2
4)=(a-c/2)^2-b^2
=(a+b-c/2)(a-b-c/2)
5)=-2...
全部展开
1)=(a-1)(a-2)x^2+(2a^2-4a+1)x+a(a-1)y^2
=[(a-1)x+ay][(a-2)x+(a-1)y]
2) =(3xy-2mn)(xy-5mn)
3)=(x-2y)^2+6z(x-2y)+9z^2
=(x-2y+3z)^2
4)=(a-c/2)^2-b^2
=(a+b-c/2)(a-b-c/2)
5)=-2x^ny^n(x^4n-2x^2ny^2+y^4)
=-2x^ny^n(x^2n-y^2)^2
1.十字相乘法
2.公式法
3.分组分解法
4.主元法
5.构造法
6.换元法
收起