法国风格的发给①BO是∠ABC的平分线,CO是∠ACB的平分线,设∠A=x°,求∠O图———— http://hi.baidu.com/%E8%AC%E7%F3%C5%C4/album/item/3b9792c4b90e49ebd10060a2.html#IMG=5a8700ef0520d21062d09fa3 ②BO是∠ABC与∠ACB的
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/01 23:07:30
![法国风格的发给①BO是∠ABC的平分线,CO是∠ACB的平分线,设∠A=x°,求∠O图———— http://hi.baidu.com/%E8%AC%E7%F3%C5%C4/album/item/3b9792c4b90e49ebd10060a2.html#IMG=5a8700ef0520d21062d09fa3 ②BO是∠ABC与∠ACB的](/uploads/image/z/2732958-54-8.jpg?t=%E6%B3%95%E5%9B%BD%E9%A3%8E%E6%A0%BC%E7%9A%84%E5%8F%91%E7%BB%99%E2%91%A0BO%E6%98%AF%E2%88%A0ABC%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%EF%BC%8CCO%E6%98%AF%E2%88%A0ACB%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%EF%BC%8C%E8%AE%BE%E2%88%A0A%3Dx%C2%B0%EF%BC%8C%E6%B1%82%E2%88%A0O%E5%9B%BE%E2%80%94%E2%80%94%E2%80%94%E2%80%94+http%3A%2F%2Fhi.baidu.com%2F%25E8%25AC%25E7%25F3%25C5%25C4%2Falbum%2Fitem%2F3b9792c4b90e49ebd10060a2.html%23IMG%3D5a8700ef0520d21062d09fa3+%E2%91%A1BO%E6%98%AF%E2%88%A0ABC%E4%B8%8E%E2%88%A0ACB%E7%9A%84)
法国风格的发给①BO是∠ABC的平分线,CO是∠ACB的平分线,设∠A=x°,求∠O图———— http://hi.baidu.com/%E8%AC%E7%F3%C5%C4/album/item/3b9792c4b90e49ebd10060a2.html#IMG=5a8700ef0520d21062d09fa3 ②BO是∠ABC与∠ACB的
法国风格的发给
①BO是∠ABC的平分线,CO是∠ACB的平分线,设∠A=x°,求∠O
图———— http://hi.baidu.com/%E8%AC%E7%F3%C5%C4/album/item/3b9792c4b90e49ebd10060a2.html#IMG=5a8700ef0520d21062d09fa3
②BO是∠ABC与∠ACB的外角的平分线,设∠A=x°,求∠O
图————http://hi.baidu.com/%E8%AC%E7%F3%C5%C4/album/item/3b9792c4b90e49ebd10060a2.html#IMG=3b9792c4b90e49ebd10060a2
法国风格的发给①BO是∠ABC的平分线,CO是∠ACB的平分线,设∠A=x°,求∠O图———— http://hi.baidu.com/%E8%AC%E7%F3%C5%C4/album/item/3b9792c4b90e49ebd10060a2.html#IMG=5a8700ef0520d21062d09fa3 ②BO是∠ABC与∠ACB的
∠O=1/2∠A=1/2X
∵OC平分∠ACE,BO平分∠ABC
∴∠OCE=1/2∠ACE ∠OBC=1/2∠ABC
∵∠ACE=∠ABC+∠A
1/2∠ACE=1/2∠ABC+∠O
即1/2∠ACE=1/2∠ABC+1/2∠A
②∠O=90°+1/2∠A=90°+1/2X
∵∠A=X,∴∠ABC+∠ACB=180°-X°
又∵∠ABC+∠CBO+∠OBE+∠ACB+∠BCO+∠OCF=360°*2=720°
∴∠CBO+∠OBE+∠BCO+∠OCF=
360°-(180°-X)=180°+x
∵OB,OC分别平分∠CBE和∠BCF
∴∠CBO+∠BCO=1/2(180°+x)=90°+1/2X
∠O=180°-(900°+1/2X)=90°+1/2X
不懂可以再问哦
什么题目啊 ?
发给我 就Ok的啦
1, ∠ABE=∠A+∠ACB
∠OBC=∠O+∠OCB
∠ABE=2∠OBE ∠ACB=2∠OCB
故:∠O=1/2∠A
∠O=1/2X
∵OC平分∠ACE,BO平分∠ABC
∴∠OCE=1/2∠ACE ∠OBC=1/2∠ABC
∵∠ACE=∠ABC+∠A
1/2∠ACE=1/2∠ABC+∠O
即1/2∠ACE=1/2∠ABC+1/2∠A
②∠O=90°+1/2∠A=90°+1/2X
∵∠A=X,∴∠ABC+∠ACB=180°-X°
又∵∠ABC+∠CBO+∠OBE+...
全部展开
∵OC平分∠ACE,BO平分∠ABC
∴∠OCE=1/2∠ACE ∠OBC=1/2∠ABC
∵∠ACE=∠ABC+∠A
1/2∠ACE=1/2∠ABC+∠O
即1/2∠ACE=1/2∠ABC+1/2∠A
②∠O=90°+1/2∠A=90°+1/2X
∵∠A=X,∴∠ABC+∠ACB=180°-X°
又∵∠ABC+∠CBO+∠OBE+∠ACB+∠BCO+∠OCF=360°*2=720°
∴∠CBO+∠OBE+∠BCO+∠OCF=
360°-(180°-X)=180°+x
∵OB,OC分别平分∠CBE和∠BCF
∴∠CBO+∠BCO=1/2(180°+x)=90°+1/2X
∠O=180°-(900°+1/2X)=90°+1/2X
收起