已知全集U={(x,y)|x∈R,y∈R},集合A={(x,y)|(y-4)/(x-2)=3},B={(x,y)|y=3x-2},则(CuA)∩B=_______________
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![已知全集U={(x,y)|x∈R,y∈R},集合A={(x,y)|(y-4)/(x-2)=3},B={(x,y)|y=3x-2},则(CuA)∩B=_______________](/uploads/image/z/3942895-31-5.jpg?t=%E5%B7%B2%E7%9F%A5%E5%85%A8%E9%9B%86U%3D%EF%BD%9B%EF%BC%88x%2Cy%29%7Cx%E2%88%88R%2Cy%E2%88%88R%EF%BD%9D%2C%E9%9B%86%E5%90%88A%3D%EF%BD%9B%28x%2Cy%29%7C%28y-4%29%2F%28x-2%29%3D3%EF%BD%9D%2CB%3D%EF%BD%9B%28x%2Cy%29%7Cy%3D3x-2%EF%BD%9D%2C%E5%88%99%EF%BC%88CuA%29%E2%88%A9B%3D_______________)
已知全集U={(x,y)|x∈R,y∈R},集合A={(x,y)|(y-4)/(x-2)=3},B={(x,y)|y=3x-2},则(CuA)∩B=_______________
已知全集U={(x,y)|x∈R,y∈R},集合A={(x,y)|(y-4)/(x-2)=3},B={(x,y)|y=3x-2},则(CuA)∩B=_______________
已知全集U={(x,y)|x∈R,y∈R},集合A={(x,y)|(y-4)/(x-2)=3},B={(x,y)|y=3x-2},则(CuA)∩B=_______________
这题很有迷惑性,集合A
一般人都会认为
两边乘以x-2再移项就OK了,实际上却忘了得出的集合应为:
A={(x,y)|y=3x-2,x≠2}
所以CuA={(2,4)}
所以(CuA)∩B={(2,4)}
=={(x,y)|y=3x-2,(x,y)不=(2,4)}
cfv
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