已知数列{an}满足a1=0,a2=2,且对任意m、n∈N*都有a2m-1+a2n-1=2am+n-1+2(m-n)2(1)求a3,a5;(2)设bn=a2n+1-a2n-1(n∈N*),证明:{bn}是等差数列;
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![已知数列{an}满足a1=0,a2=2,且对任意m、n∈N*都有a2m-1+a2n-1=2am+n-1+2(m-n)2(1)求a3,a5;(2)设bn=a2n+1-a2n-1(n∈N*),证明:{bn}是等差数列;](/uploads/image/z/7206342-6-2.jpg?t=%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97%7Ban%7D%E6%BB%A1%E8%B6%B3a1%3D0%2Ca2%3D2%2C%E4%B8%94%E5%AF%B9%E4%BB%BB%E6%84%8Fm%E3%80%81n%E2%88%88N%2A%E9%83%BD%E6%9C%89a2m-1%2Ba2n-1%3D2am%2Bn-1%2B2%EF%BC%88m-n%EF%BC%892%EF%BC%881%EF%BC%89%E6%B1%82a3%2Ca5%EF%BC%9B%EF%BC%882%EF%BC%89%E8%AE%BEbn%3Da2n%2B1-a2n-1%EF%BC%88n%E2%88%88N%2A%EF%BC%89%2C%E8%AF%81%E6%98%8E%EF%BC%9A%7Bbn%7D%E6%98%AF%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%EF%BC%9B)
已知数列{an}满足a1=0,a2=2,且对任意m、n∈N*都有a2m-1+a2n-1=2am+n-1+2(m-n)2(1)求a3,a5;(2)设bn=a2n+1-a2n-1(n∈N*),证明:{bn}是等差数列;
已知数列{an}满足a1=0,a2=2,且对任意m、n∈N*都有a2m-1+a2n-1=2am+n-1+2(m-n)2
(1)求a3,a5;
(2)设bn=a2n+1-a2n-1(n∈N*),证明:{bn}是等差数列;
已知数列{an}满足a1=0,a2=2,且对任意m、n∈N*都有a2m-1+a2n-1=2am+n-1+2(m-n)2(1)求a3,a5;(2)设bn=a2n+1-a2n-1(n∈N*),证明:{bn}是等差数列;
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