初一数学题 速度进已知m²+m-1=0,则m³+2m²+2010=_____.若m²+n²=6n-4m-13,则m²-n²=_____.观察下列各式:1³=1²,1³+2³=3²,1³+2³+3³=6²,1³+2³+3³+4&su
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![初一数学题 速度进已知m²+m-1=0,则m³+2m²+2010=_____.若m²+n²=6n-4m-13,则m²-n²=_____.观察下列各式:1³=1²,1³+2³=3²,1³+2³+3³=6²,1³+2³+3³+4&su](/uploads/image/z/7635541-13-1.jpg?t=%E5%88%9D%E4%B8%80%E6%95%B0%E5%AD%A6%E9%A2%98+%E9%80%9F%E5%BA%A6%E8%BF%9B%E5%B7%B2%E7%9F%A5m%26sup2%3B%2Bm-1%3D0%2C%E5%88%99m%26sup3%3B%2B2m%26sup2%3B%2B2010%3D_____.%E8%8B%A5m%26sup2%3B%2Bn%26sup2%3B%3D6n-4m-13%2C%E5%88%99m%26sup2%3B-n%26sup2%3B%3D_____.%E8%A7%82%E5%AF%9F%E4%B8%8B%E5%88%97%E5%90%84%E5%BC%8F%EF%BC%9A1%26sup3%3B%3D1%26sup2%3B%2C1%26sup3%3B%2B2%26sup3%3B%3D3%26sup2%3B%2C1%26sup3%3B%2B2%26sup3%3B%2B3%26sup3%3B%3D6%26sup2%3B%2C1%26sup3%3B%2B2%26sup3%3B%2B3%26sup3%3B%2B4%26su)
初一数学题 速度进已知m²+m-1=0,则m³+2m²+2010=_____.若m²+n²=6n-4m-13,则m²-n²=_____.观察下列各式:1³=1²,1³+2³=3²,1³+2³+3³=6²,1³+2³+3³+4&su
初一数学题 速度进
已知m²+m-1=0,则m³+2m²+2010=_____.
若m²+n²=6n-4m-13,则m²-n²=_____.
观察下列各式:1³=1²,1³+2³=3²,1³+2³+3³=6²,1³+2³+3³+4³=10²…观察等式左边各项幂的底数与右边幂的底数的关系,猜一猜可以得出什么规律并把这规律用等式写出来:_____.
过程要详细!符合初一的解题方式啊!
初一数学题 速度进已知m²+m-1=0,则m³+2m²+2010=_____.若m²+n²=6n-4m-13,则m²-n²=_____.观察下列各式:1³=1²,1³+2³=3²,1³+2³+3³=6²,1³+2³+3³+4&su
m³+2m²+2010
=m³+m²-m+m²+m+2010
=m*(m²+m-1)+m²+m+2010
=m²+m-1+2011
=2011
m²+n²=6n-4m-13
m²+4m+4+n²-6n-+9=0
(m+2)²+(n-3)²=0
m=-2 n=3 因为任何式的平方大于等于0,根据该式两组式均为0.
m²-n²=4-9=-5
1^3+2^3+……(n-1)^3+n^3=[n(n+1)/2]^2
前n个数的立方和 === 前n个数的和 的平方
1, 由m²+m-1=0可得m²+m=1,m³+2m²+2010=m(m²+2m)+2010=m(1+m)+2010=m²+m+2010=2011
2, (m+2)²=-(n-3)²,左边有平方,只积大于等于0,右边有个负号,知积小于等于0,要使两者相等,只能是(m+2)²=0,-(n-3)&s...
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1, 由m²+m-1=0可得m²+m=1,m³+2m²+2010=m(m²+2m)+2010=m(1+m)+2010=m²+m+2010=2011
2, (m+2)²=-(n-3)²,左边有平方,只积大于等于0,右边有个负号,知积小于等于0,要使两者相等,只能是(m+2)²=0,-(n-3)²=0,可得m=-2,n=3。则m²-n²=-5。
3, 这道题还要再想想
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