cos2α-sin2α可以化成(sinα-cosα)(sinα+cosα)吗?2α是 coa方α
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cos2α-sin2α可以化成(sinα-cosα)(sinα+cosα)吗?2α是 coa方α
cos2α-sin2α可以化成(sinα-cosα)(sinα+cosα)吗?2α是 coa方α
cos2α-sin2α可以化成(sinα-cosα)(sinα+cosα)吗?2α是 coa方α
(sinα-cosα)(sinα+cosα) = sina^2-cosa^2 = A
cos2α-sin2α = cosa^2-sina^2-2sinacosa =B
A+B = -2sinacosa 应该不能化
sin2αcosα-sinα/sin2αcos2α
cos2α-sin2α可以化成(sinα-cosα)(sinα+cosα)吗?2α是 coa方α
cosα×cos2α+sinα×sin2α
(sinα+sin2α)/(1+cosα+cos2α)
sin2α+cos2α等于
化简sin2α+cos2α
sin2αcos2α=
sin2α+cos2β=?
((1+cos2α)/(3sin2α))*((2sin^2(α))/cos2α)的化简
((1+cos2α)/(3sin2α))*((2sin^2(α))/cos2α)的化简 急
((1+cos2α)/(3sin2α))*((2sin^2(α))/cos2α)的化简
sin2α+sin2α÷3sin2α+cos2α
sin2α+sin2β-sin2αsin2β+cos2αcos2β=1 证明
关于三角函数证明证明sinα2次方a+sin2次方β-sin2次方a*sin2次方β+cos2次方a*cos2次方β=1
化简(sin2α+sinα)/(2cos2α+2sin^2α+cosα)
已知cos^4a/cos^2β+sin^4a/sin2^β=1 求证cos^4β/cos^2a+sin^4β/sin^2a=1要证cos^4β/cos^2a+sin^4β/sin^2a=1只需证cos^4βsin2α+sin^4βcos2α=cos2αsin2α(1-sin2β)cos2βsin2α+(1-cos2β)sin2βcos2α=cos2αsin2αcos2βsin2α+sin2βcos2α-sin2
运用tanα/2=sinα/1+cosα=1-cosα/sinα化简1+sin2α-cos2α/1+sin2α+cos2α
sin2α是否等于cos2α