As in figure 2.In the circular ring of which center is point O.if AO⊥BO,and the area of the shAs in figure 2.In the circular ring of which center is point O.if AO⊥BO,and the area of the shadowy part is 25cm2 ,then the area of the circuiar
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![As in figure 2.In the circular ring of which center is point O.if AO⊥BO,and the area of the shAs in figure 2.In the circular ring of which center is point O.if AO⊥BO,and the area of the shadowy part is 25cm2 ,then the area of the circuiar](/uploads/image/z/8649339-51-9.jpg?t=As+in+figure+2%EF%BC%8EIn+the+circular+ring+of+which+center+is+point+O%EF%BC%8Eif+AO%E2%8A%A5BO%2Cand+the+area+of+the+shAs+in+figure+2%EF%BC%8EIn+the+circular+ring+of+which+center+is+point+O%EF%BC%8Eif+AO%E2%8A%A5BO%2Cand+the+area+of+the+shadowy+part+is+25cm2+%2Cthen+the+area+of+the+circuiar)
As in figure 2.In the circular ring of which center is point O.if AO⊥BO,and the area of the shAs in figure 2.In the circular ring of which center is point O.if AO⊥BO,and the area of the shadowy part is 25cm2 ,then the area of the circuiar
As in figure 2.In the circular ring of which center is point O.if AO⊥BO,and the area of the sh
As in figure 2.In the circular ring of which center is point O.if AO⊥BO,and the area of the shadowy part is 25cm2 ,then the area of the circuiar ring equals to
(π ≈3.14)
(A)147 (B)157 (C)167 (D)177
请给出过程.
As in figure 2.In the circular ring of which center is point O.if AO⊥BO,and the area of the shAs in figure 2.In the circular ring of which center is point O.if AO⊥BO,and the area of the shadowy part is 25cm2 ,then the area of the circuiar
Let OC=r, OA=R,
then R^2/2 - r^2/2 = 25
R^2 - r^2 = 50
Area of the ring = πR^2 - πr^2 = π (R^2 - r^2) = 50π = 157